Authentication issue with bash script-CodePudding

It works ("klist -A" shows valid principal):

password="<some_pwd>"  
user="karim"  
department="JUS" 
echo $password | kinit $user@$domain.GOV 
Password for [email protected]:

But with the script I got the error:

Enter Password :Password for [email protected]: kinit: Password incorrect while getting initial credentials
*Password for [email protected]: kinit: Password incorrect while getting initial credentials
*Password for [email protected]: kinit: Password incorrect while getting initial credentials

Each password's letter typing leads to the above message.

Script:

#!/bin/bash

password="" 
echo "Provide user: " 
read user

echo "Provide department's name (JUS, FIN, MIL): " 
read department

pass_var="Provide password:" 
while IFS= read -p "$pass_var" -r -s -n letter 
do
            if [[ $letter == $'\0' ]]
            then
                break
            fi
            password=password "$letter"
            pass_var="*"
            if [[ $department == JUS ]];then
                echo $password | kinit $user@$department.GOV
            fi 
done

Also, if user specify the department as JUS, FIN or MIL then the kinit command should be executed with the correct set department. I tried something like that but it does not work:

if [[ $department == JUS || FIN || MIL ]];then

CodePudding user response：

Just fixing obvious errors:

#!/bin/bash

password=""

read -p "Provide username: " user
read -p "Provide department's name (JUS, FIN, MIL): " department

pass_var="Provide password: "

while IFS= read -p "$pass_var" -r -s -n 1 letter 
do
    if [[ $letter == $'\0' ]]
    then
        break
    fi
    password="$password$letter"
    pass_var="*"
done
echo

if [[ $department == JUS ]]
then
    echo "$password" | kinit "$user@$department.GOV"
fi

You can use a case or bash's =~ to match departments:

# ...
if [[ $department =~ JUS|FIN|MIL ]]
then
    echo ...
fi

# ...
case "$department" in
    JUS|FIN|MIL) echo ... ;;
esac