There are lots of special characters in these text file I get and I am trying to find and replace them with other strings. For example:
s = "BRAND~*HP*5250*RAM128*GPUAMD7990*~"
df = re.findall('BRAND~*(. ?)*~', s)
print(df)
The result yield ['*']
I want the result to be HP*5250*RAM128*GPUAMD7990
How do I achieve this?
CodePudding user response：
Escape the * in the pattern:
s = "BRAND~*HP*5250*RAM128*GPUAMD7990*~"
out = re.findall('BRAND~\*(. ?)\*~', s)
Output:
['HP*5250*RAM128*GPUAMD7990']
CodePudding user response：
You need to escape the '*'s:
df = re.findall('BRAND~\*(. ?)\*~', str)
CodePudding user response：
You want to
- match the
*asterisk as a normal 'character, and - strip the remaining
*
PS: I see your question has been edited. You may discard the 'strip' part. It seems you did not need that anymore.
[match / find]
import re
## find match based on regex pattern
df = re.findall('BRAND~\*(. ?)\*~', str)
df
[out]
['HP*5250*RAM128*GPUAMD7990']
[strip / remove]
r = re.compile('(\*)')
[r.sub('', w) for w in df]
out
['HP5250RAM128GPUAMD7990']
PS: Others might assist with a more python code!
PS: You may want to take note of Find and replace string values in list [duplicate]
CodePudding user response：
A pair of lookarounds will get the center.
(?<=BRAND~\*).*?(?=\*~)
https://regex101.com/r/zdkmYD/1
But to replace specific characters within that match requires a callback function.