I am trying to split strings containing python functions, so that the resulting output keeps separate functions as list elements.
s='hello()there()' should be split into ['hello()', 'there()']
To do so I use a regex lookahead to split on the closing paranthesis, but not at the end of the string.

While the lookahead seems to work, I cannot keep the ) in the resulting strings as suggested in various posts. Simply splitting with the regex discards the separator:

import re
s='hello()there()'
t=re.split("\)(?!$)", s)

This results in: 'hello(', 'there()'] .

s='hello()there()'
t=re.split("(\))(?!$)", s)

Wrapping the separator as a group results in the ) being retained as a separate element: ['hello(', ')', 'there()'] As does this approach using the filter() function:

s='hello()there()'
u = list(filter(None, re.split("(\))(?!$)", s)))

resulting again in the paranthesis as a separate element: ['hello(', ')', 'there()']

How can I split such a string so that the functions remain intact in the output?

CodePudding user response：

Use re.findall()

1. \w \(\) matches one or more word characters followed by an opening and a closing parenthesis> That part matches the hello() and there()

t = re.findall(r"\w \(\)", s)

['hello()', 'there()']

Edition:

s = "hello(x, ...)there(6L)now()"

t = re.findall(r"\w \(.*?\)", s)       
print(t)

['hello(x, ...)', 'there(6L)', 'now()']

CodePudding user response：

You can split on a lookbehind for () and negative lookahead for the end of the string.

t = re.split(r'(?<=\(\))(?!$)', s)