Here is a test file contains links and names within the <a></a> tags.

/tmp/test_html.txt

<tr>
<td><a href="http://www.example.com/link1">example link 1</a></td>
</tr>
<tr>
<td><a href="http://www.example.com/link2">example link 2</a></td>
</tr>
<tr>
<td><a href="http://www.example.com/link3">example link 3</a></td>
</tr>
<tr>
<td><a href="https://www.example.com/4/0/1/40116601-1FDC-real-world-link/bar" target="_blank" >Real World Link</a>&nbsp;</td>
</tr>

The following command can find out all links from the file, but it can't print the link and name together:

How to strip out all of the links of an HTML file in Bash or grep or batch and store them in a text file

# sed -n 's/.*href="\([^"]*\).*/\1/p' /tmp/test_html.txt

I want the command can print all links line by line with the name first, and then following the href.

Here is the expected output:

# sed <...command....> /tmp/test_html.txt

example link 1 | http://www.example.com/link1
example link 2 | http://www.example.com/link2
example link 3 | http://www.example.com/link3
Real World Link | https://www.example.com/4/0/1/40116601-1FDC-real-world-link/bar

How to write the sed command?

CodePudding user response：

This might work for you (GNU sed):

sed -En 's/.*href="([^"]*)"[^>]*>([^<]*)<.*/\2 | \1/p' file

Filter lines using the -n option and make regexp easier using -E option.

Match on lines containing href followed by inner text and format as required using back references.

CodePudding user response：

This solution seems to work; please mark as correct or post a comment to explain why it is not correct; thanks!

cat input3 | sed -n 's/^.*<a href="\(.*\)">example link\( [0-9][0-9]*\)<\/a><\/td>$/example link\2 | \1/p'