I'm trying to find a simple command to checkout a tag and preserve the branch name from where the tag belongs to. I am aware that tags are not necessarily attached to branches but rather commits. I'm also aware that I could achieve this in multiple commands, like:

1. Find branch name by parsing out response from: git branch -a --contains <tag>.
2. git fetch.
3. git switch <branch-name-found-in-step-1>.

But since you don't know what you don't know, I'm wondering if there's a one-line command to achieve this, something like: git switch --tag <tag> that automagically does what I want. If something like that does not exist, what would be the simplest way to accomplish what I'm looking for?

CodePudding user response：

Here is a shot at a one liner:

git switch -C $(git branch -r --format="%(refname:lstrip=3)" --contain <tag>) <tag>

Some explanations:

• git branch -r ...: only list remote branches, do not mix local and remote if some local branches were already present

• --format="%(refname:lstrip=3)": remove the leftmost 3 chunks from the full ref name for a remote branch : refs/remotes/origin/<keep only that part>

• git switch -C <branch> <tag>: if for some reason a local <branch> already existed in your repo, git switch <branch> would switch to that branch, in its current state. With -C (uppercase C) and <tag>, you will always have a branch pointing at <tag>.