How can i match this expression, and remove the last word?-CodePudding

Update: XAUUSD LONG
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/\bUpdate\b.*\b(short|long)\b/gi

Gives me:

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I want:

Update: XAUUSD
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Basically want to remove the word long or short if Update: XAUUSD exists.

CodePudding user response：

You can switch the capture groups capturing the first part instead. In the replacement use capture group 1.

Using a case insensitive match:

\b(Update\b.*)\b(?:short|long)\b

See a regex101 demo.

CodePudding user response：

If I understand your question correctly, the first line is the only one that matters. You also didn't mention what language you're using - is it just in a text editor?

You can replace this pattern (case insensitive) to an empty string:

(?<=update:\s*xauusd) (short|long)\b

It uses a positive lookbehind.