A two-dimensional array, how to remove all of the same element array-CodePudding

Suppose two dimensional array int [and] array=new int [700700];
A total of 700 * 700 type int values
Now need to carries on the comparison to these values, the same numerical array divided into a group, endures List List1=new List (a); The
Such as array [0, 0]=1 array [10, 10]=1 array [0]=1 array [110220]=1
So list1={" array [0, 0] ", "array [10, 10]", "array [0]", "array [110220]"}
Similarly, other values the same endures list2, list3,... The
How much the same set of values, will save many a list

CodePudding user response:

Simple and crude binary

 
Int [and] array=new int [700, 700]. 
Dictionary Result=new Dictionary (a); 

for (int i=0; I & lt; 700; I++) 
{
For (int j=0; J & lt; 700; J++) 
{
Int v=array (I, j), 
String s=$array "[{I}, {j}]". 
If (result. Either ContainsKey (v)) 
{
Result [v]. Add (s); 
} 
The else 
{
Result. The Add (v, new List {s}); 
} 
} 
}

CodePudding user response:

Thank you very much
Ask a question
How about a Dictionary The inside of the same element according to whether the value for cutting group
Returns the result is a multiple Dictionary Type (in a few specific groups, see a few of the same value)

CodePudding user response:

reference 1st floor Denuin response:

simple binary

 
Int [and] array=new int [700, 700]. 
Dictionary Result=new Dictionary (a); 

for (int i=0; I & lt; 700; I++) 
{
For (int j=0; J & lt; 700; J++) 
{
Int v=array (I, j), 
String s=$array "[{I}, {j}]". 
If (result. Either ContainsKey (v)) 
{
Result [v]. Add (s); 
} 
The else 
{
Result. The Add (v, new List {s}); 
} 
} 
}

thank you
Ask a question
How about a Dictionary The inside of the same element according to whether the value for cutting group
Returns the result is a multiple Dictionary Type (in a few specific groups, see a few of the same value)