Php foreach multiple arrays with if condion-CodePudding

I am trying to foreach multiple arrays with if condition, I have 3 arrays like below :

$contents = array('content1', 'content2', 'content3', 'content4');    
$types = array('pdf', 'pdf', 'txt', 'pdf');    
$links = array('link1', 'link2', 'link3');

foreach ($contents as $key => $value) {
            
            echo "$value<br>";
            
        if ($types[$key] == 'pdf') {
             echo "$links[$key]<br>";
        }

}

Output is like this :
content1
link1
content2
link2
content3
content4

Links array has 3 values, others 4 . I want if content type is pdf use link value there if not skip. And i want output like below:

content1
link1
content2
link2
content3
content4
link3

thanks for your help

CodePudding user response：

If the arrays are not the same length then you won't be able to use the key. You could use another variable to keep track of the key needed in $links or you can advance the pointer of $links each time:

foreach ($contents as $key => $value) {
    echo "$value<br>\n";
        
    if ($types[$key] == 'pdf') {
         echo current($links) . "<br>\n";
         next($links);
    }
}

CodePudding user response：

In this scenario, you need to skip forward the links array so you can do it by adding an else statement. try this code

$contents = array('content1', 'content2', 'content3', 'content4');
$types = array('pdf', 'pdf', 'txt', 'pdf');
$links = array('link1', 'link2', 'link3');

$skip_links_array = 0;

foreach ($contents as $key => $value) {

    echo "$value<br>";

    if ($types[$key] == 'pdf') {
        echo $links[$key   $skip_type]."<br>";
    }else{
        $skip_type--;
    }

}

Demo