Dividing 2 dictionary of different dictionary structure-CodePudding

I would like to divide 2 dictionary of different structure, I have found my desired result but I feel that my code is too long for this question. Is there a smarter alternative?

I have a dictionary of only d2

d2 = {3: {'good best third': 1, 'mind third': 0, 'bad third': 0}, 2: {'good so second': 0, 'mind second': 1, 'bad second': 2}, 1: {'good': 2, 'mind': 0, 'bad': 1}}

and then want to divide by the sum of all values in responding of the parent key. For simple explanation, which I have written it as below:

d1 = {3: 1, 2: 3, 1: 3}

The goal is to calculate d3, where

dict3 = d2 / d1

My code

import copy
temp = []
all_vote_len_dict = {3: {'good best third': 1, 'mind third': 0, 'bad third': 0}, 2: {'good so second': 0, 'mind second': 1, 'bad second': 2}, 1: {'good': 2, 'mind': 0, 'bad': 1}}
d1 = copy.deepcopy(all_vote_len_dict)
d2 = copy.deepcopy(all_vote_len_dict)
# to know total number of vote received per unique post
for key, values in d1.items():
    temp.append(sum(values.values()))
    temp.append(sum(values.values()))
    temp.append(sum(values.values()))
counter=0
for keys, values in d1.items():
    for key, value in values.items():
        values[key]=temp[counter]
        counter  =1
dict3={}
for (k,dict1), (k2,dict2) in zip(d1.items(), d2.items()):
    dict3[k]=({k: (dict2[k] / dict1[k]) for k in dict1})

dict3

Result of dict3

{3: {'good best third': 1.0, 'mind third': 0.0, 'bad third': 0.0},
 2: {'good so second': 0.0,
  'mind second': 0.3333333333333333,
  'bad second': 0.6666666666666666},
 1: {'good': 0.6666666666666666, 'mind': 0.0, 'bad': 0.3333333333333333}}

Is there a smarter alternative?

CodePudding user response：

The code below does the "trick"

d2 = {3: {'good best third': 1, 'mind third': 0, 'bad third': 0},
      2: {'good so second': 0, 'mind second': 1, 'bad second': 2}, 1: {'good': 2, 'mind': 0, 'bad': 1}}

d1 = {k: sum(vv for vv in v.values()) for k, v in d2.items()}
# d1 is {3: 1, 2: 3, 1: 3}
d3 = {k: {kk: vv / d1[k] for kk, vv in v.items()} for k, v in d2.items()}
for k, v in d3.items():
    print(f'{k} -> {v}')

output

3 -> {'good best third': 1.0, 'mind third': 0.0, 'bad third': 0.0}
2 -> {'good so second': 0.0, 'mind second': 0.3333333333333333, 'bad second': 0.6666666666666666}
1 -> {'good': 0.6666666666666666, 'mind': 0.0, 'bad': 0.3333333333333333}