How to replace values of a list with values of another list based on index-CodePudding

I am wondering if I can replace values of a list with elements of another list based on the index in Python:

let's say

a=[3, 2, 8, 7, 0]
d=['a','b','c','d','e','f','g','h','i']

I want to replace the elements of list a with the elements of list d. Values of list a define the index number of list d.

I want a list like c,

c=['d','c','i','a']

CodePudding user response：

a = [3,2,8,7,0]
b = ['a','b','c','d','e','f','g','h','i']
l = [b[i] for i in a]
# d, c, i, a

CodePudding user response：

a=[3, 2, 8, 7, 0]
d=['a','b','c','d','e','f','g','h','i']
d = np.array(d)
d[[a]]

This can be done with the help of numpy.

CodePudding user response：

I would do it in this manner: (anyway I am curious if there is another, simplest way)

c=[]
a=[3, 2, 8, 7, 0]
d=['a','b','c','d','e','f','g','h','i']
for index in a:
    c.append(d[index])

print(c)

result: c = ['d', 'c', 'i', 'h', 'a']