Comparing values of a list with multiple list [duplicate]-CodePudding

I am trying to compare y with x, such that it will return the amount of matches and it strictly follows the value of y.

For example, in this scenario, it should return a count of 2 as there are 2 matches of ['a', 'b'].

x = ['a', 'b'], ['b', 'c'], ['d', 'c'], ['a', 'b']
y = ['a', 'b']

CodePudding user response：

Use the list 'count' method.

x = [['a', 'b'], ['b', 'c'], ['d', 'c'], ['a', 'b']]
y = ['a', 'b']

my_count = x.count(y) # 2

CodePudding user response：

If I understand what you want, the result will be 2, so you have to iterate through the x list and for each value compare it with y, right?

x = [['a', 'b'], ['b', 'c'], ['d', 'c'], ['a', 'b']]
y = ['a', 'b']
sum = 0
for i in x:
  if i == y:
    sum =1
print(sum)