Find the index of similiar elements in lists-CodePudding

I have these two lists:

list_1 = ['less', 'more', 'more', 'more', 'more', 'more', 'more', 'more']

list_2 = ['less', 'less', 'less', 'more', 'less', 'less', 'more', 'less']

I want to find the index in list_1 if the corresponding element in the other list is the same. For example list_1[0] = list_2[0] , 0 would be the first element of the index list I am looking for but list_1[1] != list_2[1], so 1 would not be in my list

CodePudding user response：

You can first zip them, then check two by two and with enumerate save index like below. (as I ask and you say two list have same size)

Try this:

>>> list_1 = ['less', 'more', 'more', 'more', 'more', 'more', 'more', 'more']
>>> list_2 = ['less', 'less', 'less', 'more', 'less', 'less', 'more', 'less']
>>> [idx for idx, (a,b) in enumerate(zip(list_1, list_2)) if a==b]
[0, 3, 6]

# for more details
>>> list(zip(list_1, list_2))
[('less', 'less'),
 ('more', 'less'),
 ('more', 'less'),
 ('more', 'more'),
 ('more', 'less'),
 ('more', 'less'),
 ('more', 'more'),
 ('more', 'less')]

CodePudding user response：

you can use

[i for i in range(len(list_1)) if list_1[i]==list_2[i]]

if the lists are of the same length

out:

[0, 3, 6]