I have 2 arrays of the following format:

array1 = ['cat', 'man', 'new']
array2 = ['catch', 'jim', 'manners', 'renew', 'newcomer']

I am trying to find an array that contains items of array 2 if any of the strings in array 1 are contained in the string of array 2. In this case the output would be: ['catch', 'manners', 'renew', 'newcomer'] I know that I could to this with a forloop but am curious if there is a simpler 1 line solution for this?

Thanks!

CodePudding user response：

You can use RegExp.test() and Array.join() to create a regular expression using alternation:

const array1 = ['cat', 'man', 'new'];
const array2 = ['catch', 'jim', 'manners', 'renew', 'newcomer'];

const result = array2.filter(v => RegExp(array1.join('|')).test(v));

console.log(result);

Notes:

• You have to be careful when the strings include special characters, they will need to be escaped.
• From a performance perspective, it's better to build the RegExp once instead of creating it inside the filter() callback.

CodePudding user response：

With filter(), some() and includes() this can be done in one line:

let array1 = ['cat', 'man', 'new'];
let array2 = ['catch', 'jim', 'manners', 'renew', 'newcomer'];

let ans = array2.filter(x => array1.some(a => x.includes(a)));

console.log(ans);

CodePudding user response：

array1 = ['cat', 'man', 'new']
array2 = ['catch', 'jim', 'manners', 'renew', 'newcomer']

const result = array2.filter(word => array1.some(phrase => word.includes(phrase)))
console.log(result)

You can use filter() and some()