I need a program which finds exponents-CodePudding

b = int(input("Enter 2nd num \n"))
i = 1

while True:
    d = a/b
    e = d
    f = e/b
    i  = 1
    if f == 1:
        break



print(f"Exponent xyzz: {i}")

For example of I give 64 as A and 4 as B, it shall return 3......, like that. Please help. There is some bug in this code.

CodePudding user response：

def myLog(x, b):
    if x < b:
        return 0  
    return 1   myLog(x/b, b)

refer to:

Get logarithm without math log python

CodePudding user response：

In your code, you are not taking user input for 1st num, so that is first bug. Secondly a and b are constants, so d value is always same everytime the loop is executed and the loop will never break. We have to update A so that A becomes 1 while multiple division and the loop terminates. You can try doing this:

a=int(input("Enter 1st num \n"))
b = int(input("Enter 2nd num \n"))
i = 0

while True:
    a = a/b
     i  = 1
    if a == 1:
        break



print(f"Exponent xyzz: {i}")

Well check the indentation because I've copied and pasted it here since I was not able to upload image