I use this implementation for frontend: https://developer.paypal.com/demo/checkout/#/pattern/server

my frontend in particular:

............
// Call your server to set up the transaction
          createOrder: function (data, actions) {
            return fetch("/createOrder", {
              method: "post",
              credentials: "same-origin",
              headers: {
                "X-CSRFToken": csrftoken,
              },
            })
              .then(function (res) {
                console.log("res");
                console.log(res);
                return res;
              })
              .then(function (orderData) {
                console.log("orderData");
                console.log(orderData);
                return orderData.id;
              });
          },
......................

My backend:

def sth(request):
    logger.error('called')
    t = gettoken()
    d = {"intent": "CAPTURE","purchase_units": [{"amount": {"currency_code": "USD","value": "100.00"}}]}
    h = {"Content-Type": "application/json", "Authorization": "Bearer " t}
    r = requests.post('https://api-m.sandbox.paypal.com/v2/checkout/orders', headers=h, json=d).json()
    logger.error(r)
    return r

Python console (logger.error(r)):

{'id': '597275692P0354804', 'status': 'CREATED', 'links': [{'href': 'https://api.sandbox.paypal.com/v2/checkout/orders/597275692P0354804', 'rel': 'self', 'method': 'GET'}, {'href': 'https://www.sandbox.paypal.com/checkoutnow?token=597275692P0354804', 'rel': 'approve', 'method': 'GET'}, {'href': 'https://api.sandbox.paypal.com/v2/checkout/orders/597275692P0354804', 'rel': 'update', 'method': 'PATCH'}, {'href': 'https://api.sandbox.paypal.com/v2/checkout/orders/597275692P0354804/capture', 'rel': 'capture', 'method': 'POST'}]}

My errorcode in Frontend

Uncaught Error: Expected an order id to be passed

For me it looks like the response doesn't reacht my frontend. Do i missed something?

CodePudding user response：

change your middle section to

.then(function (res) {
            console.log("res");
            console.log(res);
            return res.json();
          })

you might also need to wrap it in a response

probably JSONResponse but i think in this case a normal HTTPResponse is sufficient

in python

return HTTPResponse(content=json.dumps(r))