I am making a project for local development with dockerized apps. I have 3 different domain on my company that each domain has one docker-compose file with 5 services. (15 projects)
If User of my project wants to deploy only 1 service of their domain or/and 2 of the other domains projects, I have to comment out services in other docker-compose files that dont want to be deployed.
So my question is How can i comment out docker-compose(Go) files block with bash script? I want to choose the lines with their context. For example in below example i want to comment out ap2-php-fpm section. I cant make a work around solution because more projects incoming. I have to intervene go language script with bash script.
Demonstration
version: '3.3'
services:
app-php-fpm:
container_name: app
build:
context: ${src}/
volumes:
- $path:path
networks:
general-nt:
aliases:
- app
expose:
- "9000"
ap2-php-fpm:
container_name: app
build:
context: ${src}/
volumes:
- $path:path
networks:
general-nt:
aliases:
- app
expose:
- "9000"
networks:
general-nt:
external: true
I want to make this file as below with bash script.
version: '3.3'
services:
app-php-fpm:
container_name: app
build:
context: ${src}/
volumes:
- $path:path
networks:
general-nt:
aliases:
- app
expose:
- "9000"
# ap2-php-fpm:
# container_name: app
# build:
# context: ${src}/
# volumes:
# - $path:path
# networks:
# general-nt:
# aliases:
# - app
# expose:
# - "9000"
networks:
general-nt:
external: true
CodePudding user response:
For many practical purposes, it may be enough to run docker-compose up
with specific service names. If you run
docker-compose up -d app-php-fpm
it will start the service(s) on the command line, and anything it depends_on:
, but not anything else. That would avoid the need to comment out parts of the YAML file. You could otherwise interact with the containers normally.