Faced a problem while processing hex numbers. When running str (hex ()) from a file, the zeros after 0x... disappear.

At the entrance:

0x0000000000000000000000000000000000000000000000000000000000000001f01f80f12f7cf16638f7a8074d46fe2f421a73432b1441a01ed3dd883c68acad
0x00000000000000000000000000000000000000000000000000000000000000029a799033fc54073346f870c15c9836f6b2e9eccdb85f09d29a8ddc90dc3a8ef1
0x00000000000000000000000000000000000000000000000000000000000000033e561483073e429ec25c09c99de2a81d5a34a539ad2dbb688af6b6f5f24936a4

On exit:

0x1f01f80f12f7cf16638f7a8074d46fe2f421a73432b1441a01ed3dd883c68acad
0x29a799033fc54073346f870c15c9836f6b2e9eccdb85f09d29a8ddc90dc3a8ef1
0x33e561483073e429ec25c09c99de2a81d5a34a539ad2dbb688af6b6f5f24936a4

Code:

   with open("data.txt", "r") as file:
        for line in file:
            L = int(line, 0)
            R = str(hex(L))
            print(R)

What needs to be fixed in the code? I need one size of numbers and no loss of zeros.

CodePudding user response：

Use string formatting:

• # means put 0x on the front for hex numbers.
• 0130 means the fields is 130 characters long, the leading zero means pad with zeros.
• x means hexadecimal (lowercase a-f).

line = '0x0000000000000000000000000000000000000000000000000000000000000001f01f80f12f7cf16638f7a8074d46fe2f421a73432b1441a01ed3dd883c68acad'
print(line)  # as read from file
integer = int(line, 0)
formatted = f'{integer:#0130x}'
print(formatted)
print(formatted == line) # check that original and re-formatted are the same

Output:

0x0000000000000000000000000000000000000000000000000000000000000001f01f80f12f7cf16638f7a8074d46fe2f421a73432b1441a01ed3dd883c68acad
0x0000000000000000000000000000000000000000000000000000000000000001f01f80f12f7cf16638f7a8074d46fe2f421a73432b1441a01ed3dd883c68acad
True