I have this notice message in the frontend of my Wordpress:
"Notice: Only variables should be passed by reference in..."
The notice is for this line of PHP code:
$parent_id = array_pop( wp_filter_object_list( $items, array( 'title' => $args->submenu ), 'and', 'ID' ) );
Here is the full PHP code:
add_filter( 'wp_nav_menu_objects', 'get_submenu', 10, 2 );
function get_submenu( $items, $args ) {
if ( empty($args->submenu) ) {
return $items;
}
$parent_id = array_pop( wp_filter_object_list( $items, array( 'title' => $args->submenu ), 'and', 'ID' ) );
$children = submenu_get_children_ids( $parent_id, $items );
foreach ( $items as $key => $item ) {
if ( ! in_array( $item->ID, $children ) ) {
unset($items[$key]);
}
}
return $items;
}
function submenu_get_children_ids( $id, $items ) {
$ids = wp_filter_object_list( $items, array( 'menu_item_parent' => $id ), 'and', 'ID' );
foreach ( $ids as $id ) {
$ids = array_merge( $ids, submenu_get_children_ids( $id, $items ) );
}
return $ids;
}
I don't success to remove the notice by resolving the issue. Thanks in advance for the help.
CodePudding user response:
Try this:
$filter_items = wp_filter_object_list( $items, array( 'title' => $args->submenu ), 'and', 'ID' );
$parent_id = array_pop( $filter_items );
The reason is that the wp_filter_object_list array is passed by reference because it is modified by the function array_pop. It means that you need to pass array_pop a real variable and not a function.