I am new to java, why a, b,c initialization are wrong in the following code.
public static void main(String[] args) {
if (args.length < 2)
throw new IllegalArgumentException ("we need 2 argumeents");
else {
int a = Integer.parseInt(args[0]);
int b = Integer.parseInt(args[1]);
int c = a b;
}
System.out.println(a " " b " = " c);
}
CodePudding user response:
Java works differently compared to JavaScript. Every {} block has an own variable scope. Variables defined inside a block are not visible outside.
public static void main(String[] args) {
{
int x=1;
System.out.println(x); // prints 1
}
{
int x=2;
System.out.println(x); // prints 2
}
// System.out.println(x); // error: cannot find symbol
}