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Bash: collect the data (two parameters) between two keywords(variable string) from ini file

Time:10-19

I have a txt.ini file with content (I cannot modify the structure of this file):

txt.ini

txt.ini

[person_0:public]
name=john
groups=0,1,2
age=30

[person_0:private]
married=false
weight=190
height=100

[person_1:public]
name=mark
groups=0,4
age=28

[person_1:private]
married=false
weight=173
height=70

[person_2:public]
name=tony
groups=3,4
age=30

[person_3:private]
married=true
weight=202
height=120

I have a variable "person" which takes the value one of: person_0, person_1, person_3 in the loop and I would like to collect the person's data like age and groups for every 'person' one by one.

My idea is to cut out the part between $person:public and $person:private and after that collect

e.g. set variable person=person_1 output: groups=0,4 age=28

I prepared the code in bash (persons is a list of person_0, person_1, person2):

for person in ${persons[@]}; do
    file="txt.ini"
    echo "$person"
    a=$(awk -v a=$person":private" -v b=$person":public" '/a/{found=0} {if(found) print} /b/{found=1}' $file)

    IFS=$'\n' lines=($a)
    IFS='=' read grouplist grouplist_values <<< ${lines[1]}
    IFS='=' read age age_values <<< ${lines[4]}
    echo "Group list = $grouplist_values"
    echo "Age = $age_values"

Group list and age are empty. Output:

person_0
Group list =
Age =

person_1
Group list =
Age =

person_2
Group list =
Age =

Expected:

person_0
Group list =0,1,2
Age =30

person_1
Group list =0,4
Age =28

person_2
Group list =3,4
Age =30

I will use this data "per person" in another part of my code. I'm working on files with different number of "persons".

I really don't know what is wrong.

I tried also:

#export person="person_0"
#a=$(awk '/ENVIRON["person"]:private/{found=0} {if(found) print} /ENVIRON["person"]:public/{found=1}' $file)

and

private=$person":private"
public=$person":public"
echo "private=$private"
echo "public=$public"
a=$(awk -v a=$private" -v b=$public '/a/{found=0} {if(found) print} /b/{found=1}' $config_file)

but output was the same:

person_0
private=person_0:private
public=person_0:public
Group list =
Age =

What is strange for me - when I hardcode range of cutting it works properly:

a=$(awk '/person_0:private/{found=0} {if(found) print} /person_0:public/{found=1}' $file)

or

a=$(awk '/person_1:private/{found=0} {if(found) print} /person_1:public/{found=1}' $file)

Do you have any idea how can I collect this data in a clever way?

CodePudding user response:

Assumptions:

  • for a given person (eg, person_0) display said person along with the associated (public) fields for groups and age
  • no indication has been given for what we're suppose to do with this data so assume, for now, we just need to print to stdout
  • list of persons to process is in bash array persons[]
  • the strings :public and :private only show up in the block headers

One awk idea where we use the split() function to parse a line based on different delimiters:

awk '
FNR==NR    { persons[$1]
             next
           }
/:private/ { printme=0 }
/:public/  { printme=0

             split($1,arr,"[]:[]")
             person=arr[2]

             if (person in persons) {
                printme=1
                printf "%s%s\n", pfx, person
                pfx="\n"
             }
           }
printme    { split($1,arr,"=")
             if (arr[1] == "groups") print "Group list =" arr[2]
             if (arr[1] == "age")    print "Age ="        arr[2]
           }
' <(printf "%s\n" "${persons[@]}") txt.ini

A variation on this theme using a multi-character input field delimiter:

awk -F"[]:=[]" '
FNR==NR       { persons[$1]
                next
              }
$3=="private" { printme=0 }
$3=="public"  { printme=0
                if ($2 in persons) {
                   printme=1
                   printf "%s%s\n", pfx, $2
                   pfx="\n"
                }
              }
printme && $1=="groups" { print "Group list =" $2 }
printme && $1=="age"    { print "Age ="        $2 }
' <(printf "%s\n" "${persons[@]}") txt.ini

With:

$ typeset -p persons
declare -a persons=([0]="person_0" [1]="person_1" [2]="person_2")

Both sets of awk code generate:

person_0
Group list =0,1,2
Age =30

person_1
Group list =0,4
Age =28

person_2
Group list =3,4
Age =30

NOTE: this could be made more dynamic (public and/or private? different fields?) but that'll entail a bit more coding

CodePudding user response:

Would you please try the following:

awk -v RS='' '                          # split the records on the blank lines
/public/ {                              # "public" record
    split($1, a, /[\[:]/); print a[2]   # extract the "person_xx" substring
    for (i = 2; i <= NF; i  ) {         # iterate over the lines of the record
        split($i, a, /=/)
        if (a[1] == "groups") print "Group list =" a[2]
        else if (a[1] == "age") print "Age =" a[2]
    }
    print ""                            # insert a blank line
}
' txt.ini

Output:

person_0
Group list =0,1,2
Age =30

person_1
Group list =0,4
Age =28

person_2
Group list =3,4
Age =30

  • By setting awk variable RS to the null string, the records are separated by blank lines and the fields are separated by the newline character.
  • Assuming the desired data are included in the public block, we can parse the filelds of the public record one by one.
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