How to create i copies of a numpy array and name them differently for i in a range?-CodePudding

I have an array (oned_2018) and I want a function to make multiple copies of this array. The number of copies is the largest value in this array. e.g. largest is 6; then there should be 6 copies. Could anyone please help me write this loop? I want something like...

for i in range(1, max(oned_2018) 1):
    classi_20 = oned_2018.copy() # of course this line is incorrect!

and outputs should be like this manual work:

class1_20 = oned_2018.copy()

class2_20 = oned_2018.copy()

class3_20 = oned_2018.copy()

class4_20 = oned_2018.copy()

class5_20 = oned_2018.copy()

class6_20 = oned_2018.copy()

CodePudding user response：

If you really want to to so, you can use globals():

oned_2018 = [1, 2, 3, 4]
for i in range(1, max(oned_2018) 1):
    globals()[f"class{i}_20"] = oned_2018.copy() # of course this line is incorrect!

print(class1_20) # [1, 2, 3, 4]

But dynamically creating variables like this is generally avoided. Usually people would recommend using dict instead:

oned_2018 = [1, 2, 3, 4]
data = {f"class{i 1}_20": oned_2018.copy() for i in range(max(oned_2018))}

print(data['class1_20']) # [1, 2, 3, 4]

CodePudding user response：

Instead of naming them by variable, I would suggest you to use a dictionary as such:

classes_to_data = {}
for i in range(1, max(oned_2018) 1):
    classes_to_data[i] = oned_2018.copy()

Then, you can access them as follows:

classes_to_data[1]  # outputs what you named 'class1_20'
classes_to_data[2]  # outputs what you named 'class2_20'
# and so on...