So I have 3 fragments, fragmentA
, fragmentB
and fragmentC
in fragmentA I create a viewpager with 2 tabs (fragmentB
and fragmentC
)
FragmentA
private fun setupTabLayoutWithViewPager() {
binding.viewPager.disableUserSwipeLeftRight()
binding.viewPager.adapter = MyCustomStateAdapter(this, this)
val tabLayout = binding.tabLayout
TabLayoutMediator(tabLayout, binding.viewPager) { tab, position ->
tab.text = when (position) {
0 -> ResourceUtils.getString(R.string.firstTab)
1 -> ResourceUtils.getString(R.string.secondTab)
else -> emptyString()
}
}.attach()
tabLayout.allowEachTabWithEqualWidth()
}
now , from fragmentB
and fragmentC
that are created with this MyCustomStateAdapter
I want to share the viewmodel between them, so in my fragmentA since its the parent of these two fragments I did this for the instance of the viewmodel
FragmentA
private val viewModel: MyViewModel by viewModels(ownerProducer = { requireParentFragment() }) {
createVMFactory {
MyViewModel(
MyRepo()
)
}
}
Now, do I need to paste this same exact code in fragmentB
and fragmentC
to access the instance of the viewmodel created by fragmentA
? because I want to share this same viewmodel between these 3 fragments
Thanks
CodePudding user response:
So in fragmentA it should be
private val viewModel: MyViewModel by viewModels {
createVMFactory {
MyViewModel(
MyRepo()
)
}
}
and in the other fragments (the tab ones)
private val viewModel: MyViewModel by viewModels(ownerProducer = { requireParentFragment() }) {
createVMFactory {
MyViewModel(
MyRepo()
)
}
}
since we create the first viewmodel with the ownerProducer as this (the parent fragment) and its childs will get the parent fragment and get the viewmodel instance stored on this owner
CodePudding user response:
You can share data between fragment in one activity with activityViewModel. Maybe this codelab will help you