if/else/while not executing conditions python-CodePudding

I'm a beginner in Python and I'm struggling to find my mistake. I have 3, now two conditions for input, and not sure what the problem is. I have tried implementing in various ways, from using all if statements then if/else, then nesting as well as while loop. I'm not sure what I'm doing wrong.

def switch_off():
    robot_name
    answer = input (robot_name   ": what must I do next? " )
    
    if answer == "OFF":    
         quit()   
    if answer.lower() != "off":
        print( robot_name   ": Shutting down...")
    if answer== "OFF" or answer.lower() != "off":
        print(robot_name   ": Sorry, I did not understand")
        answer = input (robot_name   ": what must I do next? " )

CodePudding user response：

Did you call the function at the end of your code? Also you need to input a value for your 'robot_name' variable!

You can call the function by typing this at the end of your code:

switch_off()

*PS. I know this isn't what you asked, but your if-else statements give very odd returns and should be optimized!

For example, when I input 'k' into the console, it returns this:

Bob: what must I do next? k
Bob: Shutting down...
Bob: Sorry, I did not understand
Bob: what must I do next?

You can fix this by making sure your if-else statements dont overlap each other!

Hopefully this helps :)

CodePudding user response：

I really don't know what you really want but try this

using while loop you can loop through and give orders.

def switch_off():
    robot_name
    answer = input(robot_name   ": what must I do next? ")
    while True:
        if answer == "OFF":   
            quit()
        elif answer.lower() != "off":
            print( robot_name   ": Shutting down...")
            break
        elif answer=="OFF" or answer.lower() != "off":
            print(robot_name   ": Sorry, I did not understand")
            answer = input (robot_name   ": what must I do next? " )
            break

CodePudding user response：

I don't know what your end goal is, but I hope this helps.

To run this function, you to call it. I added "switch_off()" at the end of the code.
We will encounter an error (NameError) because "robot_name" is not defined, meaning it's not set equal to anything. In my example code below I set it equal to "AI". Now your code will run.
I am not sure what your intentions are, but I will explain my example code below (hopefully it'll help). When you run the switch_off function, it will prompt you with "AI: what must I do next?". If you type in "OFF", it will quit the program. If you don't type "OFF", but type "off" then the program will print "AI: Shutting down...". And if you type something other than "OFF" or "off", it will repeat the function by calling it again (see how I have switch_off in the "else:")
Note that == means equal, and != means not equal. Also keep in mind that "else:" will always run if the previous if and/or elif aren't true.

def switch_off():
    robot_name = "AI"
    answer = input (robot_name   ": what must I do next? " )
    
    if answer == "OFF":    
         quit()   
    elif answer.lower() == "off":
        print( robot_name   ": Shutting down...")
    else:
        print(robot_name   ": Sorry, I did not understand")
        switch_off()
              
switch_off()