Is it possible to specify a member-function template parameter pack? Something like this:
template <typename foo, void (foo::*bar)(void) ...>
void application()
{
}
None of my solutions work, and I would like to avoid putting every function that I'm gonna use in a struct.
CodePudding user response:
The syntax for this is
template <typename C, void (C::*...mfuncs)()>
void application()
{
// ...
}
or with typedef
:
template <typename C>
using MemberFunc = void (C::*)();
template <typename C, MemberFunc<C>...mfuncs>
void application();