#include <stdio.h>
#include <stdlib.h>
int main()
{
int i;
for(i=1; i<5; i )
{
printf(" %d Perulangan %d \n ", i);
}
return 0;
}
Please help me for the correct My Code looping (C Language) , i want print this output :
1 perulangan 1
2 perulangan 2
3 perulangan 3
4 perulangan 4
CodePudding user response:
Super easy to do. Just add in an additional i parameter for the 2nd %d like so:
#include <stdio.h>
#include <stdlib.h>
int main()
{
int i;
for(i=1; i<5; i )
{
printf(" %d Perulangan %d \n ", i, i);
}
return 0;
}
CodePudding user response:
One would normally just repeat the argument.
printf("%d Perulangan %d\n", i, i);
Alternatively, a POSIX-compliant compiler will accept references to arguments by position:
printf("%1$d Perulangan %1$d\n", i);