Python Selenium - find item in a list-CodePudding

I have the following:

<a href="/firewall_aliases.php" class="navlnk">Aliases</a>
<a href="/firewall_aliases.php" class="navlnk">NAT</a>
<a href="/firewall_aliases.php" class="navlnk">Rules</a>

I can't seem to be able to locate the element with text Aliases. Is it possible to do?

Can anyone help me out?

CodePudding user response：

You can use the following XPath locator:

//a[text()="Aliases"]

For more uniqueness you can use

//a[@href="/firewall_aliases.php" and (text()="Aliases")]

Or even

//a[@href="/firewall_aliases.php" and (@class="navlnk") and (text()="Aliases")]

CodePudding user response：

To locate the element with text as Aliases you can use either of the following Locator Strategies:

Using link_text:

element = driver.find_element(By.LINK_TEXT, "Aliases")

Using css_selector:

element = driver.find_element(By.CSS_SELECTOR, "a.navlnk[href*='firewall_aliases']")

Using xpath:

element = driver.find_element(By.XPATH, "//a[text()='Aliases' and contains(@href, 'firewall_aliases')]")

Ideally, to locate the element you need to induce WebDriverWait for the visibility_of_element_located() and you can use either of the following Locator Strategies:

Using LINK_TEXT:

element = WebDriverWait(driver, 20).until(EC.visibility_of_element_located((By.LINK_TEXT, "Aliases")))

Using CSS_SELECTOR:

element = WebDriverWait(driver, 20).until(EC.visibility_of_element_located((By.CSS_SELECTOR, "a.navlnk[href*='firewall_aliases']")))

Using XPATH:

element = WebDriverWait(driver, 20).until(EC.visibility_of_element_located((By.XPATH, "//a[text()='Aliases' and contains(@href, 'firewall_aliases')]")))

Note : You have to add the following imports :

from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC

CodePudding user response：

You can use like:

//*[text()="Aliases"]

another way is

//a[@href="/firewall_aliases.php" and (text()="Aliases")]