Let's say I have a file following this pattern

112;167;82
16;104;2
24;163;3
67;195;48

I want each number to be converted in hexadecimal.

70;A7;52
10;68;02
18;A3;03
43;C3;30

printf '%x\n' does work but only for one instance at once.

CodePudding user response：

while IFS=';' read -a n ; do
    printf 'X;' "${n[@]}"
    echo
done < file | sed 's/;$//'

• read -a reads each line into an array, setting IFS sets the separator, i.e. the elements of the array will be the numbers on each line;
• The printf line prints each element of the array followed by a ;, the trailing semicolon is removed in the sed command afterwards.
• echo adds a newline at the end of each printed array.

CodePudding user response：

bash:

while IFS=';' read -ra line;  do
    line=$(printf '%x;' "${line[@]}")
    echo "${line%;}"
done < file

awk (probably faster for a larger file):

awk '
    BEGIN {FS=OFS=";"}
    {for (i=1; i<NF; i  ) {
            $i = sprintf ("%x", $i)
         }
     print}' my-file

CodePudding user response：

awk -F ';' '{print toupper(sprintf("x;x;x",$1,$2,$3))}' file

Output:

70;A7;52
10;68;02
18;A3;03
43;C3;30

CodePudding user response：

Using sed

$ sed 's/;/ /g;s/.*/printf "x" & /e;s/[a-z0-9]\{2\}/\U&;/2;s/[a-z0-9]\{2\}/\U&;/' input_file

In order for the printf command to run, ; needs to be removed after which printf "x" can be executed.

Output

70;A7;52
10;68;02
18;A3;03
43;C3;30