Using Excel and I'd like a formula that will return the earliest date from a row that contain duplicate date. for example: my row has 5 different dates, 1 duplicate and one blank cell
A B C D E F
09/01/2021 08/28/2021 09/08/2021 blank cell 09/01/2021 08/15/2021
I am using formula =MIN((A1:F1)
the return should be "8/28/2021" but I'm getting "1/1/1900" can someone please help? that will be greatly appreciated
CodePudding user response:
Try this:
=MIN(IFERROR(A1:F1*A1:F1/A1:F1,99999))
It will replace all the 0's with 99999 if it cannot be divided by itself (0).
(99999 is actually 10/13/2173 and was chosen at random as a date that will be later than the other dates on your list.)
CodePudding user response:
You can do it with SMALL function:
My formula in column J is =SMALL(A1:G1;1)
Notice my date format is dd/mm/yyyy