i have a following String that i get with Ansible debug module:

{
    "ansible_facts": {
        "discovered_interpreter_python": "/usr/libexec/platform-python"
    },
    "changed": true,
    "cmd": [
        "check"
    ],
    "stderr_lines": [],
    "stdout": "QMNAME(XXXXXX)                                STATUS(Running)",
    "stdout_lines": [
        "QMNAME(XXXXXX)                                STATUS(Running)"
    ]
}

The 'XXXXXXXX' varieties from server to server.

How can i get it?

i need to reuse it as part of systemd module:

- name: Check Status of the Services 
  systemd:
    name: "{{ item }}"
    state: started
  with_items:
    - "my-{{ server.stdout | regex_search('\\(([^()] )\\)', '\\1') | trim }}-server"
  when: ('server' in group_names)

i have tried to trim it and cut it but since the size differs i get to less or to much.

- name: Check my_Server output
  debug:
    msg: "{{ server.stdout[7:-48] | trim }}"
  failed_when: "'STATUS(Running)' not in server.stdout"
  when: ('server' in group_names)

CodePudding user response：

You can use the following to get the first string between parentheses excluding the parentheses themselves:

{{ server.stdout | regex_search('\\(([^()] )\\)', '\\1') | trim }}
{{ server.stdout | regex_search('\\(([^()] )\\)', '\\1') | list | first | trim }}

The \(([^()] )\) pattern matches a ( first, then one or more chars other than ( and ) (that are captured into Group 1, hence the \1 later), and then a ) char is matched, but not captured.

Using trim is still fine since the captured substring may still contain whitespace at the start and end.

To get multiple matches use

{{ server.stdout | regex_findall('\\(\\s*([^()]*?)\\s*\\)') }}

The \(\s*([^()]*?)\s*\) matches

• \( - a ( char
• \s* - zero or more whitespaces
• ([^()]*?) - Group 1 (the return result of regex_findall): any zero or more chars other than ( and ) as few as possible (so that the subsequent \s* could consume all whitespace chars before ))
• \s* - zero or more whitespaces
• \) - a ) char.