I am trying to know more about how paths work in python and I encountered the next problem.

When I try to call the full path I use the following -> "./Folder/archive2", and this works perfectly well when my .py file is in the same directory as the folder containing this 'archive2', but lets say the following:

    - Archive1 is in Folder1 (both archives are .py files)
    - Archive2 is in Folder2
    - Folder1 and Folder2 are in "RandomDirectory"
    

How can I get the path of Archive2 in Archive1 if they are in the same RandomDirectory but in different folders. Of course, copying the path is not an option because I want it to work on any computer so something like "./Folder/archive" would be great, so if I run the .py in other computer it would work as normal.

Thanks for reading.

CodePudding user response：

Use .. to refer to the parent of the current directory.

If your working directory is Archive1, then:

• .. refers to Folder1
• ../.. refers to RandomDirectory
• ../../Folder2 refers to RandomDirectory/Folder2
• and ../../Folder2/Archive2 refers to RandomDirectory/Folder2/Archive2.

CodePudding user response：

if you have a structure like this:

Randomdirectory
├── Folder1
│   └── Archive1.py
└── Folder2
    └── Archive2.py

you can access Archive2.py from Archive1.py like this:

# code in Archive1.py
from pathlib import Path

print(Path('../Folder2/Archive2.py').exists())

CodePudding user response：

In general you can use os library like this:

import os.path as pt

archive2_path = pt.join(pt.split(pt.dirname(pt.abspath(__file__)))[0], 'Folder2/Archive2.py')

In this case archive2_path is absolute path of Archive2.