for job in jobs:
if int(dpr) <= int(user.dpr):
if str(user.gender) == 'male:
if str(orpi) == 'yes':
if int(profil) >= int(user.profil):
bot.send_message(message.chat.id, str(name)
**now i want to exit the "if's" and go to next "job in for loop**
else:
if int(profil) <= int(user.profil):
bot.send_message(message.chat.id, str(name)
**now i want to exit the "if's" and go to next "job in for loop**
else:
if str(orpi) == 'yes':
if int(profil_fem) >= int(user.profil):
bot.send_message(message.chat.id, str(name)
**now i want to exit the "if's" and go to next "job in for loop**
else:
if int(profil_fem) >= int(user.profil):
bot.send_message(message.chat.id, str(name)
**now i want to exit the "if's" and go to next "job in for loop**
Hello, I want to make "now i want to exit the "if's" and go to the next "job in for loop" in the code, return to the for loop (job in jobs), and process to the next job. Is there any command for it?
CodePudding user response:
You can use the continue keyword. It allows you to ignore everything that comes next and go to the start of the loop. For example in this case:
for i in (0, 1, 2):
print(i)
continue
print("This won't get executed")
The line after the continue will never run.