Using python I was trying to execute if and else in a single line as below
expr = "no remainder" if 5% 2 == 0 else pass
print(expr)
output:
SyntaxError: invalid syntax
Expected output:
It should pass condition without printing anything
Please help me on how to overcome the above issue
CodePudding user response：
When you use if and else in the same line what you are actually using is a conditional ternary operator. This is a way of selecting a value from two possible values based on a condition, not choosing whether to run a line based on a condition. So pass is not valid. Perhaps what you want instead is None or "" or "there is a remainder". Here is the correct code:
expr = "no remainder" if 5% 2 == 0 else "there is a remainder"
print(expr)
CodePudding user response：
You aren't using pass correctly. You should return a value in the else block. The pass statement is a null operation; nothing happens when it executes, so you're variable would be empty when the condition is not met. You might want to return something like None instead.
CodePudding user response：
As others mentioned, pass is not supposed to be used like this. If you want to execute the print() statement conditionally, do something like this:
expr = "no remainder" if 5 % 2 == 0 else None
if expr:
print(expr)
CodePudding user response：
s = 12 if 3 < 4 else 32
assign 12 if 3 is less than 4,else assign 32.