I have created a Dockerfile which I am using to build and run an image. Now the image that I am creating using Dockerfile requires another Docker image to execute a python script.
My Dockerfile:
FROM python:3
ADD test.py /test.py
CMD ["python", "test.py"]
To execute test.py, I need to have landoop/fast-data-dev image. Can someone give idea how to achieve this.
CodePudding user response：
Your dockerfile should look like this:
FROM python:3 as test
WORKDIR /app/
ADD test.py /app/
FROM landoop/fast-data-dev
COPY --from=test /app/test.py /app/
WORKDIR /app/
CMD ["python", "test.py"]
CodePudding user response：
I’m having trouble understanding your question. I think you’re asking how to python test.py in landoop/fast-data-dev image. Is that correct? if correct,so:
docker run -it -d -P --rm lensesio/fast-data-dev
docker ps -a | grep "lensesio/fast-data-dev"
my result is:
23536c30d44d lensesio/fast-data-dev "/usr/bin/dumb-init …" About a minute ago Up About a minute 0.0.0.0:49160->2181/tcp, 0.0.0.0:49159->3030/tcp, 0.0.0.0:49158->3031/tcp, 0.0.0.0:49157->8081/tcp, 0.0.0.0:49156->8082/tcp, 0.0.0.0:49155->8083/tcp, 0.0.0.0:49154->9092/tcp cool_cannon
in your brower visit 127.0.0.1:49159 [because of 0.0.0.0:49159->3030/tcp] if you want to execute python script. you can do below:
docker cp test.py 23536c30d44d:test.py
docker exec -it 23536c30d44d bash
python3 test.py
CodePudding user response：
If I understand you correctly, you are running a container from an image built from this Dockerfile, and this running container is dependent on a service provided from a different running container?
There are a couple of ways to achieve this:
The simplest is just to run this other container in detached mode (with the
-dflag), first. Then, when you run thetest.pycontainer, it should be able to contact the service it requires. You would need to stop and delete the detached one when you're finished.Another way would be to use docker compose. This allows you to deploy multiple containers in the same command.