open external file through wave.open in python-CodePudding

I'm using wave.open to open file , if i give local path

async def run_test(uri):
        async with websockets.connect(uri) as websocket:
     wf = wave.open('test.wav', "rb")

then it is working but if i give external path it is not working

async def run_test(uri):
        async with websockets.connect(uri) as websocket:
     wf = wave.open('http://localhost:8000/storage/uploads/test.wav', "rb")

getting this error :

OSError: [Errno 22] Invalid argument: 'http://localhost:8000/storage/uploads/test.wav'

CodePudding user response：

Yeah, wave.open() doesn't know anything about HTTP.

You'll need to download the file first, e.g. with requests (or aiohttp or httpx since you're in async land).

import io, requests, wave

resp = requests.get('http://localhost:8000/storage/uploads/test.wav')
resp.raise_for_status()
bio = io.BytesIO()  # file-like memory buffer
bio.write(resp.content)  # todo: if file can be large, maybe use streaming
bio.seek(0)  # seek to the start of the file
wf = wave.open(bio, "rb")  # wave.open accepts file-like objects

This assumes the file is small enough to fit in memory; if it's not, you'd want to use tempfile.NamedTemporaryFile instead.