Check a String and output false if it doesn't contain the desired element from a List-CodePudding

Could someone help me why does this code turns TRUE while I want it to turn False, because i want the output like:
Yes the string does contain x but contains Y too let's say x is asd and Y is asd 2 (with space) There is my code :

text = "asd 1"
Should_contain = ["asd 1"]
Shouldnt_contain = ["asd", "asdd"]
contains_desired_string = any(x in text for x in Should_contain)
contains_bad_string = any(x in text for x in Shouldnt_contain)
print(contains_desired_string, contains_bad_string)

(If any of the not wanted elements are in the List, it should print False).
SO it should print True False INSTEAD of True True
I think that there might be the problem because of the space.
For example if that's a webscraper that scrapes iphone listings let's say there is an iphone 6 and a iphone 6s,bot contains iphone 6 but the two listings are whole differents ones, therefore it makes sense to filter them like ,yes it contains iphone 6 but it contains iphone 6s too,therefore the program will let you know if that's an iphone 6 or iphone 6s listing, I hope that's a clear anwser for the next questions

CodePudding user response：

Any functions returns True if bool(x) is True for any x in the iterable. In your case contains_bad_string is true because the input string text contains 'asd' which is an element in Shouldnt_contain list.

As per your comment If any of the not wanted elements are in the List, it should print False , you can change contains_bad_string in this way

contains_bad_string =  not any(x in text for x in Shouldnt_contain)

CodePudding user response：

SOLUTION:

counter = 0
    if "asd" in text:
        counter = -1
    counter_haha = 0

    for x in Should_contain:
        counter  =text.count(x)

    for x in Shouldnt_contain:
        counter_haha  = text.count(x)

    if (counter > 1 and counter_haha > 0) or counter == 0:
        print(text "That means Yes it contains X and contains Y too")
    elif counter == 1 and counter_haha == 1:
        print(text "That means Yes it contains X but it does not contain Y")

(X=asd 1 Y=asd or asdd)
For example if that's a webscraper that scrapes iphone listings let's say there is an iphone 6 and a iphone 6s,bot contains iphone 6 but the two listings are whole differents ones, therefore it makes sense to filter them like ,yes it contains iphone 6 but it contains iphone 6s too,therefore the program will let you know if that's an iphone 6 or iphone 6s listing, I hope that's a clear anwser for the next questions