Create Dictionary with Variable Name Values-CodePudding

I am trying to figure out how to best create a python dictionary where the values are variable names

e.x.

ruleLst = ["gender brand","sport gender","sport gender brand"]

for i in ruleLst:
    
    new_values = i.split(" ")
    rules.update({i:new_values})

rules

returns:

{
 'gender brand': ['gender', 'brand'],
 'sport gender': ['sport', 'gender'],
 'sport gender brand': ['sport', 'gender', 'brand']
}

What I try to output is:

{
 'gender brand': [gender, brand],
 'sport gender': [sport, gender],
 'sport gender brand': [sport, gender, brand]
}

Where gender, brand, sport are lists defined in the code before ruleLst is defined.

CodePudding user response：

You can use list comprehension like:

ruleLst = ["gender brand","sport gender","sport gender brand"]
gender = ["M", "F"]
sport = ["basket", "volleyball"]
brand = [1, 2]
a = {i: [globals()[j] for j in i.split(" ")] for i in ruleLst}
print(a)

and output:

{
'gender brand': [['M', 'F'], [1, 2]],
'sport gender': [['basket', 'volleyball'], ['M', 'F']],
'sport gender brand': [['basket', 'volleyball'], ['M', 'F'], [1, 2]]
}

Reference:

CodePudding user response：

Try using globals()[new_values[0]] and globals()[new_values[1]] instead of new_values to get the variables value.
Like this:

ruleLst = ["gender brand","sport gender","sport gender brand"]
rules = {}
gender = ["male", "female"]
sport = ["basket", "volleyball"]
brand = ["x", "y"]

for i in ruleLst:
    
    new_values = i.split(" ")
    rules.update({i:[globals()[new_values[0]], globals()[new_values[1]]]})

print(rules)

CodePudding user response：

You could solve this with the map function like this. By casting it as a dict you'll get the dictonary you want.

rules = dict(map(lambda elem: [elem, elem.split(' ')], ruleLst))