Write a program that takes a character as input (string length 1) the output is the next character i-CodePudding

Write a program that takes a character as input (a string of length 1), which you should assume is an upper-case character; the output should be the next character in the alphabet.

If the input is 'Z', your output should be 'A'.

Here's what i've done so far but I’m not getting A when I input Z. I’m getting [.

Please help, what am I doing wrong?

input = (input()).upper()
for character in input:
   number = ord(character)   1
   number1 = chr(number)
   if ord('z'):
       new_number = ord(character) - 25
        number2 = chr(new_number)

print(number1)

CodePudding user response：

A way of doing this may be via a match statement:

match (letter):
    case 'A':
        print('B')
    case 'B':
        print('C')

But you will need around 30 cases...

A better idea is to use a list:

letters = ['A', 'B', 'C'...]

then to get the letter

letter = input().upper()

and then to get the next element in the list:

print(letters[letters.find(letter) 1])

but there will be an error raised for 'Z', so you will need a try/except block for IndexError:

try:
    print(letters[letters.find(letter) 1])
except IndexError:
    print('A')

CodePudding user response：

I have figured it out!! Thanks to everyone for reaching out with an alternative method! I'm ever grateful.

input = (input()).upper()
encrypted = ""
for character in input:
    if character == "":
        encrypted  = ""
elif ord(character)   1 > ord("Z"):
    encrypted  = chr(ord(character)   1 - 26)
else:
    encrypted  = chr(ord(character)   1)

print(encrypted)