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Get the 3rd part of the string in Postgres

Time:02-12

I have data like,

ab-volt-ssn-dev
ab-volt-lnid-dev
ab-volt-ssn-hamp-dev
ab-volt-cf-apnt-test

I need output to be like,

ssn
lnid
ssn
cf

CodePudding user response:

You can use split_part()

select split_part('ab-volt-ssn-hamp-dev', '-', 3);

If you need to access multiple parts, then converting it to an array might be easier:

select elements[1],
       elements[2],
       elements[3],
       elements[4]
from (
   select string_to_array(the_column, '-') as elements
   from the_table
) t;          
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