Django function params-CodePudding

Where there are a series of parameters passed to a Django function they may have defaults. If a param is supplied when the function is called it is used. If not the default is used. Is there a way to access the first default while supplying subsequent param[s] in the function call?

 Example:

    def pong(fname = 'Pinkus', lname = 'Poke'):
    print(f'My name is {fname} {lname}')
    
    pong()                          # My name is Pinkus Poke
    pong('Frank')                   # My name is Frank Poke
    pong('Frank', 'Finklestein')    # My name is Frank Finklestein
    pong('', 'Bloggs')              # only gives empty string, no default!

CodePudding user response：

You can pass the arguments as keyword arguments (kwargs) instead of positional arguments (args). This way you can specify which argument you want to set.

pong(lname='Bloggs')

CodePudding user response：

def pong(fname = 'Pinkus', lname = 'Poke'):
    if not fname:
        fname = 'Pinkus'
    if not lname:
        lname = 'Poke

    print(f'My name is {fname} {lname}')