Find line number of a value which matches upto 2 decimal in python numpy-CodePudding

I tried to find the line number of value which is 60 % of the maximum value in file.

if max_value=1
   v_60 = 0.6

My file looks like this,

2.140672782874617625e-02
9.785932721712538307e-02
1.651376146788990640e-01
2.140672782874617763e-01
2.568807339449541427e-01
2.996941896024464813e-01
3.363914373088685017e-01
3.639143730886849615e-01
3.975535168195718505e-01
4.097859327217125425e-01
4.250764525993884213e-01
4.525993883792048256e-01
4.678899082568807044e-01
4.740061162079510226e-01
4.954128440366972197e-01
5.076452599388379117e-01
5.259938837920489219e-01
5.351681957186543714e-01
5.443425076452599320e-01
5.626911314984709422e-01
5.871559633027523262e-01
6.055045871559633364e-01
6.055045871559633364e-01
6.116207951070335991e-01
6.238532110091742355e-01
8.715596330275228176e-01
8.623853211009173680e-01
8.715596330275228176e-01
8.807339449541283782e-01
8.837920489296635651e-01
8.807339449541283782e-01
8.899082568807338278e-01
8.868501529051986410e-01
9.663608562691131665e-01
9.816513761467889898e-01
9.755351681957186161e-01
9.724770642201834292e-01
9.785932721712538029e-01
9.877675840978593635e-01
1.000000000000000000e 00
1.000000000000000000e 00

Now I print the line number of the max value by

l=numpy.where(file == np.amax(file))

now how to find the line number which has 0.60 just comparing up to two decimal value only in python.

CodePudding user response：

This will find the element closest to the 60% mark:

findit = data.max() * 0.6
print(np.argmin(np.abs((data-findit))))

Output: