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How to open the last folder irrespective of name on Bash

Time:03-04

I’m currently working with a program that creates a folder with a time stamp and puts some files into it.

I want to write a script to automate retrieval of the file from last or second last folder by alphabetical order.

How do I do this on bash?

Image for reference. I want to retrieve a file from the 18-38 folder or the 17-45 folder.

enter image description here

CodePudding user response:

I want to write a script to automate retrieval of the file from last or second last folder by alphabetical order.

cd path/to/02-March-2022

last_dir=$(printf '%s\n' */ | sort | tail -n 1)
second_last_dir=$(printf '%s\n' */ | sort -r | sed '2!d; 2q'
  • You can remove or add sort's -r to switch between Nth newest and Nth oldest.

Edit:

  • Globs are always sorted alphabetically (according to current locale), so the first sort is actually superfluous. But sort is useful if you need the extra sort flags, or to sort by specific fields, suffixes, etc.
  • Both sort and pathname expansion are affected by the current locale, so consider setting LC_ALL=C for consistent behavior. (export LC_ALL=C or LC_ALL=C sort for sort to see it).

CodePudding user response:

Suppose you have these directories:

% ls -l
total 0
drwxr-xr-x  2 andrew  wheel  64 Mar  3 15:19 1
drwxr-xr-x  2 andrew  wheel  64 Mar  3 15:19 2
drwxr-xr-x  2 andrew  wheel  64 Mar  3 15:19 3
drwxr-xr-x  2 andrew  wheel  64 Mar  3 15:19 4
drwxr-xr-x  2 andrew  wheel  64 Mar  3 15:19 5

With the 'last' being 5.

You can do:

% for fn in *; do [[ -d "$fn" ]] && lf="$fn"; done
% echo "$lf"                                      
5

I cannot overstress, however, that the * may or may not give you what YOU think is the 'last directory.'

If you want to assure that it is the last one, sort them by stat and then take the last one.

CodePudding user response:

Try

folders=( path/to/02-March-2022/*/ )
last_dir=${folders[-1]%/}
second_last_dir=${folders[-2]%/}
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