I am creating this code for a project at my school, the current formula I have for adding an integer to the end of a number is: "curnumber = curnumber (integer - curnumber)", kind of like if you want x to be 13 and the current number is 2, you'd do something like "x = x (13 - 2)" and it'd return the number but I don't know how to combine the numbers, it's really confusing, I'm able to get the number from a single character using this code:
def singleint(num):
int_ = 0
if num == '0':
int_ = 0
elif num == '1':
int_ = 1
elif num == '2':
int_ = 2
elif num == '3':
int_ = 3
elif num == '4':
int_ = 4
elif num == '5':
int_ = 5
elif num == '6':
int_ = 6
elif num == '7':
int_ = 7
elif num == '8':
int_ = 8
elif num == '9':
int_ = 9
return int_`
and my total current code is:
def singleint(num):
int_ = 0
if num == '0':
int_ = 0
elif num == '1':
int_ = 1
elif num == '2':
int_ = 2
elif num == '3':
int_ = 3
elif num == '4':
int_ = 4
elif num == '5':
int_ = 5
elif num == '6':
int_ = 6
elif num == '7':
int_ = 7
elif num == '8':
int_ = 8
elif num == '9':
int_ = 9
return int_
def tonumber(str_):
num = 0
x = 0
for char in list(str(str_)):
c = singleint(char)
print(type(c))
new = (c - num)
num = num new
x = 1
return num
print(str(tonumber(192)))
I really need help with this, thanks
CodePudding user response:
I'm not 100% sure what you're asking here but I think the answer to your question is:
int(num)
That'll convert the string to an integer.
CodePudding user response:
Try to see if all the characters in a string is numeric by using isnumeric() method, and if true, then use int() to convert it.
def convert_number(string_format):
if string_format.isnumeric():
return int(string_format)
else:
return None