Given the expression n = p × k r , (0 ≤ r < k). Find the values of p and r when known n and k-CodePudding

I've been trying to do this but I'm getting an error Time Limit Exceeded, please help!

Example of input and exepected output

Input#1: 5 2
Output#1: 2 1

#include<stdio.h>
    int main(){
        long long n, k, p, r;
        scanf("%lld %lld", &n, &k);
        if (r >= 0 && r < k){
            if (n >= 1){
                p = (n - r) / k;
                r = n / (p * k);
            }
        }
        printf("%lld %lld", p, r);
        return 0;
    }

CodePudding user response：

Here you can take the reference from the code written in python, I first calculate the highest multiple of k (less than k) divisible by n. It is calculated by the // operator in python. Like, 37/5=7.4 but 37//4 gives 7 (floor of 7.4). Then I calculate r and finally prints them

# 37 = p*5   r
# take n=37 and k=5

n,k = map(int,input().split())  # take n,k as input 
p = n//k                        # it will max multiple of k divisible by n
r = n - (p*k)                   # r = 37 - (7*5)
print("p =",p," and r=",r)      # print answer here

CodePudding user response：

The variable r is not initialized and has an indeterminate value

long long n, k, p, r;

So this if statement

if (r >= 0 && r < k){

at once invokes undefined behavior.

What you need is to include the header

#include <stdlib.h>

and to use the function lldiv declared in this header that calculates the quotient and the remainder of two numbers.

Here is a demonstration program.

#include <stdlib.h>
#include <stdio.h>

int main( void )
{
    long long int n = 100, k = 13;

    lldiv_t result = lldiv( n, k );

    long long int p = result.quot;
    long long int r = result.rem;

    printf( "p = %lld, r = %lld\n", p, r );
}

The program output is

p = 7, r = 9

Or instead of the function you could use the two operators / and % like

p = n / k;
r = n % k;