Has word any of unaccepted chars?-CodePudding

please, I have an array of unaccepted characters and I want if unknown word or sentence contains any of this characters. If now, I can add it to my words array

I have the code:

// Define dictionary
let words = []

// Unaccepted characters
const unacceptedChars = [' ', '-', ',', '.']

let word = 'blue world'

if(!word.includes(unacceptedChars)) {
  console.log('This sentence doesn\'t contain any of unaccepted chars and could be used')
} else {
  console.log('Sentence can\'t be used')
}

The result is This sentence doesn't contain any of unaccepted chars and could be used which is wrong because word contains a space which is unaccepted character.

If I edit the code to

// Define dictionary
let words = []

// Unaccepted characters
const unacceptedChars = [' ']

let word = 'blue world'

if(!word.includes(unacceptedChars)) {
  console.log('This sentence doesn\'t contain any of unaccepted chars and could be used')
} else {
  console.log('Sentence can\'t be used')
}

all works OK. Result is Sentence can't be used

Please, how I look in array in Javascript? I tried find the answer but I didn't found yet. Thanks for any advice

CodePudding user response：

You can't use includes with array as parameter

the properly way is

try {
  unacceptedChars.forEach(char => {
    if(word.includes(unacceptedChars)) {
      Throw new Error('Sentence can\'t be used')
    }
  })
  console.log('This sentence doesn\'t contain any of unaccepted chars and could be used')
} catch(error => {
  console.error(error.message)
})

CodePudding user response：

Thanks for inspiration to all. My finally solution is

let words = []
const unacceptedChars = [' ', '-', '.', ',']
let newWord = $(this).text()
for (let i = 0; i < unacceptedChars.length; i  ) {
  if (newWord.includes(unacceptedChars[i])) {
    allowedWord = false
    break
  }
}
if (allowedWord) words.push(newWord)

Thanks again to all