how to replace strings in a file using a loop counter-CodePudding

I have a file named: my_file.txt

And inside this my_file.txt, I have some strings such as:

name1 name1 name1 name1 name1 name1 name1 name1 name1 name1

And I need to do a bulk loop counter on that 1 to 10 to look like:

name1 name2 name3 name4 name5 name6 name7 name8 name9 name10

So far I only have this, which I found here:

https://www.geeksforgeeks.org/how-to-search-and-replace-text-in-a-file-in-python

But that just swaps one string for another. And I need to use the counter.

search_text = "dummy"

replace_text = "replaced"

with open(r'my_file.txt', 'r') as file:

    data = file.read()
    data = data.replace(search_text, replace_text)

with open(r'my_file.txt', 'w') as file:

    file.write(data)

print("Text replaced")

CodePudding user response：

You can simply do iterative replace and replacing one occurence at each time.

Work with chunks to improve performance in case the string is very very big


with open(r'my_file.txt', 'r') as file:
    data = file.read()
    
search_text = "dummy"
replace_text = "replaced"
n_replaced = 0
index = 0


chunks = []
while True:
    index = data.find(search_text)
    if index == -1:
        break
    replace_text_counter = f"{replace_text}{n_replaced}"
    chunks.append(data[:index])
    data = data[index:].replace(search_text, replace_text_counter, 1)
    n_replaced  = 1
chunks.append(data)

with open(r'my_file.txt', 'w') as file:
    file.write("".join(chunks))

print("Text replaced")

CodePudding user response：

To ignore the read and write file and lines in your case. I give a code just deal with string line which you gave name1 name1 name1 name1 name1 name1 name1 name1 name1 name1:

string = "name1 name1 name1 name1 name1 name1 name1 name1 name1 name1"
li = string.split()
i=0
for i<len(li):
  li[i]=li[i].replace("1",i 1)
return ' '.join(li)