I would like to create a new df, based upon whether the second or third condition
's for each subject
are greater than the first condition.
Example df:
df1 <- data.frame(subject = rep(1:5, 3),
condition = rep(c("first", "second", "third"), each = 5),
values = c(.4, .4, .4, .4, .4, .6, .6, .6, .6, .4, .6, .6, .6, .4, .4))
> df1
subject condition values
1 1 first 0.4
2 2 first 0.4
3 3 first 0.4
4 4 first 0.4
5 5 first 0.4
6 1 second 0.6
7 2 second 0.6
8 3 second 0.6
9 4 second 0.6
10 5 second 0.4
11 1 third 0.6
12 2 third 0.6
13 3 third 0.6
14 4 third 0.4
15 5 third 0.4
The resulting df would be this:
> df2
subject condition values
1 1 first 0.4
2 2 first 0.4
3 3 first 0.4
4 4 first 0.4
6 1 second 0.6
7 2 second 0.6
8 3 second 0.6
9 4 second 0.6
11 1 third 0.6
12 2 third 0.6
13 3 third 0.6
14 4 third 0.4
Here, subject #5 does not meet the criteria. This is because only subject #5's values are not greater than the first condition in either the second or third condition.
Thanks.
CodePudding user response:
We may group by 'subject' and filter
if any
of the second or third 'values' are greater than 'first'
library(dplyr)
df1 %>%
group_by(subject) %>%
filter(any(values[2:3] > first(values))) %>%
ungroup
-output
# A tibble: 12 × 3
subject condition values
<int> <chr> <dbl>
1 1 first 0.4
2 2 first 0.4
3 3 first 0.4
4 4 first 0.4
5 1 second 0.6
6 2 second 0.6
7 3 second 0.6
8 4 second 0.6
9 1 third 0.6
10 2 third 0.6
11 3 third 0.6
12 4 third 0.4
CodePudding user response:
Using ave
.
df1[with(df1, ave(values, subject, FUN=\(x) any(x[2:3] > x[1])) == 1), ]
# subject condition values
# 1 1 first 0.4
# 2 2 first 0.4
# 3 3 first 0.4
# 4 4 first 0.4
# 6 1 second 0.6
# 7 2 second 0.6
# 8 3 second 0.6
# 9 4 second 0.6
# 11 1 third 0.6
# 12 2 third 0.6
# 13 3 third 0.6
# 14 4 third 0.4