Finding the multiples of 3 in a given range-CodePudding

I wrote a code that can find the multiples of 3 of a given number, but I want to make it so that it will only print out the multiples of 3 in a given range. How can I do that?

Here's my code:

def findMultiples(x):
   for x in range(1, x   1):
      if x % 3 == 0 
         print(x)

findMultiples(120)

CodePudding user response：

You don't need to loop through every number to see if it's a multiple of 3. Once you've found one, you can step through multiples only.

def findMultiples(x, y, multiple):
    # find the first value that's a multiple
    for i in range(x, x   multiple):
        if i % multiple == 0:
            break
    # step through the remaining values
    for j in range(i, y, multiple):
        print(j)

findMultiples(121, 143, 3)

CodePudding user response：

def findMultiples(x, y):
   for i in range(x, y   1):
      if i % 3 == 0 and i % 5 == 0:
         print(i)

findMultiples(120, 240)

I still don't sure what do you mean, but I think this is what you want. In your for loop, you set the wrong loop variable, it should be anything else than x.

CodePudding user response：

Use another variable name in for loop ("i" for example):

def findMultiples(x):
   for i in range(1, x   1):
      if i % 3 == 0:
         print(i)
         
findMultiples(120)

CodePudding user response：

You can use filter function The 1st argument is the function based on which filtering will happen lambda x: x%3==0 returns True or False for an input x. The input x comes from the list [i for i in range(a, b)] which is the 2nd argument to the filter function.

>>> a = 100
>>> b = 200
>>> print(list(filter( lambda x:x%3==0 , [i for i in range(a, b)])))
[102, 105, 108, 111, 114, 117, 120, 123, 126, 129, 132, 135, 138, 141, 144, 147, 150, 153, 156, 159, 162, 165, 168, 171, 174, 177, 180, 183, 186, 189, 192, 195, 198]