TypeError: reverse() takes exactly 2 arguments (1 given)-CodePudding

For some weird reason, reverse function is not working even though my url has no arguments.

Url.py:

from django.urls import path

from . import views

urlpatterns = [
    path("api/v2/app/nextdialog", views.NextDialog.as_view(), name="app-next-dialog"),
]

views.py:

class StartAssessment(generics.GenericAPIView):
    
    def post(self, request, *args, **kwargs):
        data = request.data
        request = build_rp_request(data)
        response = post_to_app_start_assessment(request)
        path = get_path(response)
        step = get_step(response)
        data["path"] = path
        data["step"] = step
        request = build_rp_request(data)
        app_response = post_to_app(request, path)
        message = format_message(app_response)
        return Response(message, status=status.HTTP_200_OK)

functions.py:

def get_endpoint(payload):
    head = {
        "Content-Type": "application/json",
    }
    url = reverse("app-next-dialog")
    response = requests.post(url, data=json.dumps(payload), headers=head)
    return response

When I run this I get the following error.

url = reverse("app-next-dialog")
TypeError: reverse() takes exactly 2 arguments (1 given)

Please does anyone have an idea what's wrong here. I wouldn't think I need to add any other arguments. Thanks

CodePudding user response：

Are you using Django reverse or DRF reverse?

Django reverse returns a relative URI when DRF reverse can return an absolute URI.

Django reverse takes 1 argument so this should work

url = reverse("app-next-dialog")

But DRF reverse takes two arguments like:

url = reverse("app-next-dialog", request=request)

Check your imports