I have the following dataframe:
| ID | date |
|--------------|-----------------------------------------|
| 0 | 2022-01-01 12:00:01 05:00 |
| 1 | 2022-01-30 21:30:01 03:00 |
| 2 | 2022-02-15 13:04:02 02:00 |
| 3 | 2022-09-05 15:30:01 00:00 |
| 4 | 2022-04-21 13:18:02 02:00 |
The date column is a python TimeStamp. I am using the python holidays library, I would like to use the following code:
from datetime import date
import holidays
usa_holidays = holidays.country_holidays('US')
texas_holidays = holidays.country_holidays('US', subdiv='TX')
florida_holidays = holidays.country_holidays('US', subdiv='FL')
california_holidays = holidays.country_holidays('US', subdiv='CA')
# df is the dataframe above
# It doesn't work.
df['only_date'] = df['date'].apply(lambda x: x.date())
df['federal_holiday'] = df['only_date'].isin(usa_holidays)
# Returns holiday name 'New Year's Day'
print(usa_holidays.get('2022-01-01'))
I would like to add the following columns:
- federal_holiday: True or False if the day is a bank holiday (country dictionary).
- holiday_state: True if it is a holiday in at least one of the state-related dictionaries. False in other case.
- name_state: names of the states in which that day is a public holiday, if it falls on all days, write all.
- holiday_name: Name of the festival.
The resulting dataframe would look as follows:
| ID | date | federal_holiday | holiday_state | name_state | holiday_name |
|----|---------------------------|-----------------|---------------|------------|----------------------|
| 0 | 2022-01-01 12:00:01 05:00 | True | True | all | New Year's Day |
| 1 | 2022-01-30 21:30:01 03:00 | False | False | NaN | NaN |
| 2 | 2022-02-15 13:04:02 02:00 | False | True | FL,CA | Susan B. Anthony Day |
| 3 | 2022-09-05 15:30:01 00:00 | True | True | all | Labor Day |
| 4 | 2022-04-21 13:18:02 02:00 | False | True | TX | San Jacinto Day |
I hope you can help me. Thank you very much in advance.
CodePudding user response:
With the following dataframe:
import holidays
import pandas as pd
pd.options.display.max_columns = 500
df = pd.DataFrame(
{
"ID": [0, 1, 2, 3, 4],
"date": [
"2022-01-01 12:00:01 05:00",
"2022-01-30 21:30:01 03:00",
"2022-02-15 13:04:02 02:00",
"2022-09-05 15:30:01 00:00",
"2022-04-21 13:18:02 02:00",
],
}
)
You could try this:
cal = {
"USA": holidays.country_holidays("US"),
"TX": holidays.country_holidays("US", subdiv="TX"),
"FL": holidays.country_holidays("US", subdiv="FL"),
"CA": holidays.country_holidays("US", subdiv="CA"),
}
fmt = "%Y-%m-%d"
df = (
df.assign(
date=lambda df_: pd.to_datetime(
df_["date"], format="%Y-%m-%d %H:%M:%S", utc=True
)
) # convert values to datetime
.assign(
federal_holiday=lambda df: df["date"].apply(
lambda x: True if cal["USA"].get(x.strftime(fmt)) else False
)
) # add a new column for federal holidays
.assign(
holiday_name=lambda df: df["date"].apply(
lambda x: cal["USA"].get(x.strftime(fmt))
)
) # add a new column for holiday name
.assign(
name_state=lambda df: df["date"].apply(
lambda x: [
state
for state, calendar in cal.items()
if calendar.get(x.strftime(fmt)) and state != "USA"
]
)
) # add a new column for state names
.assign(
holiday_name=lambda df: df["date"].apply(
lambda x: list(
set(
[
calendar.get(x.strftime(fmt))
for calendar in cal.values()
if calendar.get(x.strftime(fmt))
]
)
)
)
) # add state holiday names
.assign(
holiday_name=lambda df: df["holiday_name"].apply(
lambda x: ", ".join(x) if len(x) > 0 else pd.NA
)
) # convert list of names to string
.assign(
name_state=lambda df: df["name_state"]
.apply(lambda x: ", ".join(x) if len(x) > 0 else pd.NA)
.str.replace("TX, FL, CA", "all")
) # convert list of names to string and replace with 'all'
.assign(holiday_state=lambda df: ~df["name_state"].isna()) # add new column
.reindex(
[
"ID",
"date",
"federal_holiday",
"holiday_state",
"name_state",
"holiday_name",
],
axis=1,
) # reorder columns order
)
And so:
print(df)
# Output
ID date federal_holiday holiday_state name_state \
0 0 2022-01-01 07:00:01 00:00 True True all
1 1 2022-01-30 18:30:01 00:00 False False <NA>
2 2 2022-02-15 11:04:02 00:00 False True FL, CA
3 3 2022-09-05 15:30:01 00:00 True True all
4 4 2022-04-21 11:18:02 00:00 False True TX
holiday_name
0 New Year's Day
1 <NA>
2 Susan B. Anthony Day
3 Labor Day
4 San Jacinto Day