How to include() PHP file with just a directory path like this "folder

I am trying to run index.php file with include("folder_1")

 -- folder_1
|    -- index.php
|    -- other_stuff.php

In above mentioned directory structure. Normally to run index.php we'll write include("folder_1/index.php") . expecting to run the index.php file with include("folder_1") something like how import works in React.

Thanks :)

CodePudding user response：

There is no concept of "default file to include" in PHP. However, you can easily create a helper function to accomplish this. (Whether this makes sense or not, I leave for you to decide.)

function import(string $dir) {
    include $dir . 'index.php'; 
}

Note that if your file to import contains variables, they will be "lost" in the function's scope. If your file only defines classes, functions, constants etc. that are scope-independent, this will work fine. (Refer to my original answer for importing variables from files using a helper function.)

Edit: It turns out OP wasn't asking about including multiple files. My original answer has been ported over to: How to include() all PHP files from a directory?.

CodePudding user response：

this is not how the include method works, for doing that you need to write your custom method, can use something like that

foreach(glob('includes/*.php') as $file) {
   include($file);
}

CodePudding user response：

You can only scan directory and include each file. There is no native function.

Example:

function include_dir($path) {
    
    $files = glob($path.'/*.php');
    
    if(count($files) > 0) {
        foreach($files as $file) {
            include $file;
        }
    }

}

include_dir("./app");